What is the answer to solvefor x,sqrt(x^3)+4=-10y ?

The answer to solvefor x,sqrt(x^3)+4=-10y is x=\sqrt[3]{100y^2+80y+16} {y<=-2/5 }

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solvefor x,sqrt(x^3)+4=-10y

solve for

x, x^{3} + 4 = - 10 y

Solution steps

x^{3} + 4 = - 10 y

Move

4

to the right side

x^{3} = - 10 y - 4

Square both sides:

x^{3} = 100 y^{2} + 80 y + 16

x^{3} = 100 y^{2} + 80 y + 16

Solve

Verify Solutions:

The solution is

5 x^{2} - 5 x = 0

x, 3 x - 5 = 13

(9 - 5 x)^{2} + (6 x - 2)^{2} = 6

What is the answer to solvefor x,sqrt(x^3)+4=-10y ?
The answer to solvefor x,sqrt(x^3)+4=-10y is x=\sqrt[3]{100y^2+80y+16} {y<=-2/5 }