What is the answer to solvefor y,y^{2/3}=x ?

The answer to solvefor y,y^{2/3}=x is y=xsqrt(x) {x>= 0},y=-xsqrt(x) {x>= 0}

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solvefor y,y^{2/3}=x

solve for

y, y^{\frac{2}{3}} = x

y = x x {x \geq 0}, y = - x x {x \geq 0}

Solution steps

y^{\frac{2}{3}} = x

Take both sides of the equation to the power of

3 : y^{2} = x^{3}

y^{2} = x^{3}

Solve

y^{2} = x^{3} : y = x x, y = - x x

y = x x, y = - x x

Verify Solutions:

y = x x {x \geq 0}, y = - x x {x \geq 0}

The solutions are

y = x x {x \geq 0}, y = - x x {x \geq 0}

\frac{x}{4} = 2 x - 15

(- 3 x + 18)^{\frac{1}{2}} = x

x = 3 x + 1

4 (x - 1)^{\frac{2}{3}} = 0

x - 5 = x - 11

What is the answer to solvefor y,y^{2/3}=x ?
The answer to solvefor y,y^{2/3}=x is y=xsqrt(x) {x>= 0},y=-xsqrt(x) {x>= 0}