What is the answer to \sqrt[8]{x^2-2207x+1}=0 ?

The answer to \sqrt[8]{x^2-2207x+1}=0 is x=(2207+987sqrt(5))/2

Solve for x: \sqrt[8]{x^2-2207x+1}=0

The solution is x=(2207+987sqrt(5))/2

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x = \frac{2207 + 987 5}{2}

Decimal Notation

x = 2206.99954 \dots

Solution steps

Take both sides of the equation to the power of

8 : x^{2} - 2207 x + 1 = 0

x^{2} - 2207 x + 1 = 0

Solve

x^{2} - 2207 x + 1 = 0 : x = \frac{2207 + 987 5}{2}, x = \frac{2207 - 987 5}{2}

x = \frac{2207 + 987 5}{2}, x = \frac{2207 - 987 5}{2}

Verify Solutions:

x = \frac{2207 + 987 5}{2}

True

, x = \frac{2207 - 987 5}{2}

False

The solution is

x = \frac{2207 + 987 5}{2}

x - 4 + 9 = 14

x^{- \frac{1}{4}} = \frac{1}{3}

- 5 = 3 x - 3

0 = r + 1

500 = 4 (30 - q)

What is the answer to \sqrt[8]{x^2-2207x+1}=0 ?
The answer to \sqrt[8]{x^2-2207x+1}=0 is x=(2207+987sqrt(5))/2
Solve for x: \sqrt[8]{x^2-2207x+1}=0
The solution is x=(2207+987sqrt(5))/2