What is the answer to sqrt(2x+1)=sqrt(3x-3) ?

The answer to sqrt(2x+1)=sqrt(3x-3) is x=4

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sqrt(2x+1)=sqrt(3x-3)

2 x + 1 = 3 x - 3

x = 4

Solution steps

2 x + 1 = 3 x - 3

Square both sides:

2 x + 1 = 3 x - 3

2 x + 1 = 3 x - 3

Solve

2 x + 1 = 3 x - 3 : x = 4

x = 4

Verify Solutions:

x = 4

True

The solution is

x = 4

4 = 16.5 \cdot x^{- 1.38}

4 x^{\frac{3}{2}} - 28 = 0

75 = X^{2} + X^{2}

(x^{2} - 4)^{\frac{1}{3}} = 0

3 - x - x = 3

What is the answer to sqrt(2x+1)=sqrt(3x-3) ?
The answer to sqrt(2x+1)=sqrt(3x-3) is x=4
Solve for x: sqrt(2x+1)=sqrt(3x-3)
The solution is x=4