What is the answer to -1+sqrt(x^2-2x)=0 ?

The answer to -1+sqrt(x^2-2x)=0 is x=1+sqrt(2),x=1-sqrt(2)

Solve for x: -1+sqrt(x^2-2x)=0

The solution is x=1+sqrt(2),x=1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 1 + x^{2} - 2 x = 0

x = 1 + 2, x = 1 - 2

Decimal Notation

x = 2.41421 \dots, x = - 0.41421 \dots

Solution steps

- 1 + x^{2} - 2 x = 0

Move

1

to the right side

x^{2} - 2 x = 1

Square both sides:

x^{2} - 2 x = 1

x^{2} - 2 x = 1

Solve

x^{2} - 2 x = 1 : x = 1 + 2, x = 1 - 2

x = 1 + 2, x = 1 - 2

Verify Solutions:

x = 1 + 2

True

, x = 1 - 2

True

The solutions are

x = 1 + 2, x = 1 - 2

5 x + 9 = 7

x, y = 1 - x

x^{0.7} = 0.4 \cdot 10 0^{0.7}

5 = 6 x + 1 - 2

6 x - 5 + 7 = 3

What is the answer to -1+sqrt(x^2-2x)=0 ?
The answer to -1+sqrt(x^2-2x)=0 is x=1+sqrt(2),x=1-sqrt(2)
Solve for x: -1+sqrt(x^2-2x)=0
The solution is x=1+sqrt(2),x=1-sqrt(2)