What is the answer to sqrt(3x-1)-sqrt(x-1)=2 ?

The answer to sqrt(3x-1)-sqrt(x-1)=2 is x=2(2+sqrt(2))

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sqrt(3x-1)-sqrt(x-1)=2

3 x - 1 - x - 1 = 2

x = 2 (2 + 2)

Decimal Notation

x = 6.82842 \dots

Solution steps

3 x - 1 - x - 1 = 2

Remove square roots

4 x^{2} - 16 x + 16 = 16 x - 16

Solve

4 x^{2} - 16 x + 16 = 16 x - 16 : x = 2 (2 + 2), x = 2 (2 - 2)

x = 2 (2 + 2), x = 2 (2 - 2)

Verify Solutions:

x = 2 (2 + 2)

True

, x = 2 (2 - 2)

False

The solution is

x = 2 (2 + 2)

2 t + 6 = - 4

\frac{2 p + 6}{4} = 3

x^{4} - 2 x^{2} + 1 = x - 1

8 - x - 7 = 2 x + 8

What is the answer to sqrt(3x-1)-sqrt(x-1)=2 ?
The answer to sqrt(3x-1)-sqrt(x-1)=2 is x=2(2+sqrt(2))
Solve for x: sqrt(3x-1)-sqrt(x-1)=2
The solution is x=2(2+sqrt(2))