What is the answer to sqrt(x^2+4x-1)=2x ?

The answer to sqrt(x^2+4x-1)=2x is x= 1/3 ,x=1

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sqrt(x^2+4x-1)=2x

x^{2} + 4 x - 1 = 2 x

x = \frac{1}{3}, x = 1

Decimal Notation

x = 0.33333 \dots, x = 1

Solution steps

x^{2} + 4 x - 1 = 2 x

Square both sides:

x^{2} + 4 x - 1 = 4 x^{2}

x^{2} + 4 x - 1 = 4 x^{2}

Solve

x^{2} + 4 x - 1 = 4 x^{2} : x = \frac{1}{3}, x = 1

x = \frac{1}{3}, x = 1

Verify Solutions:

x = \frac{1}{3}

True

, x = 1

True

The solutions are

x = \frac{1}{3}, x = 1

\frac{2}{7} = x^{- 0.5}

(x + 3)^{\frac{2}{3}} - 5 = - 1

x + 1 - 4 = 2 x

What is the answer to sqrt(x^2+4x-1)=2x ?
The answer to sqrt(x^2+4x-1)=2x is x= 1/3 ,x=1
Solve for x: sqrt(x^2+4x-1)=2x
The solution is x= 1/3 ,x=1