What is the answer to 1=sqrt(x^2-3x+2) ?

The answer to 1=sqrt(x^2-3x+2) is x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

Solve for x: 1=sqrt(x^2-3x+2)

The solution is x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 = x^{2} - 3 x + 2

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Decimal Notation

x = 2.61803 \dots, x = 0.38196 \dots

Solution steps

1 = x^{2} - 3 x + 2

Square both sides:

1 = x^{2} - 3 x + 2

1 = x^{2} - 3 x + 2

Solve

1 = x^{2} - 3 x + 2 : x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Verify Solutions:

x = \frac{3 + 5}{2}

True

, x = \frac{3 - 5}{2}

True

The solutions are

x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

x + 8 = 12

- 2 3 x + 4 + 5 = - 9

2 (x^{2} + 2) = 5 x^{3} + 1

x^{\frac{1}{2}} + 3 x - 3 = 4

What is the answer to 1=sqrt(x^2-3x+2) ?
The answer to 1=sqrt(x^2-3x+2) is x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2
Solve for x: 1=sqrt(x^2-3x+2)
The solution is x=(3+sqrt(5))/2 ,x=(3-sqrt(5))/2