What is the answer to 1+sqrt(x)=(x-1)^2 ?

The answer to 1+sqrt(x)=(x-1)^2 is x=0,x=(3+sqrt(5))/2

Solve for x: 1+sqrt(x)=(x-1)^2

The solution is x=0,x=(3+sqrt(5))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 + x = (x - 1)^{2}

x = 0, x = \frac{3 + 5}{2}

Decimal Notation

x = 0, x = 2.61803 \dots

Solution steps

1 + x = (x - 1)^{2}

Remove square roots

x = x^{4} - 4 x^{3} + 4 x^{2}

Solve

x = x^{4} - 4 x^{3} + 4 x^{2} : x = 0, x = 1, x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

x = 0, x = 1, x = \frac{3 + 5}{2}, x = \frac{3 - 5}{2}

Verify Solutions:

x = 0

True

, x = 1

False

, x = \frac{3 + 5}{2}

True

, x = \frac{3 - 5}{2}

False

The solutions are

x = 0, x = \frac{3 + 5}{2}

y + 5 = 0

u, u + v = 5

x^{0.16} - x^{0.15} = 5000

x = x^{2} - 4

What is the answer to 1+sqrt(x)=(x-1)^2 ?
The answer to 1+sqrt(x)=(x-1)^2 is x=0,x=(3+sqrt(5))/2
Solve for x: 1+sqrt(x)=(x-1)^2
The solution is x=0,x=(3+sqrt(5))/2