What are the solutions to the equation -3x^2-12x-12=0 ?

The solutions to the equation -3x^2-12x-12=0 are x=-2

Find the zeros of -3x^2-12x-12=0

The zeros of -3x^2-12x-12=0 are x=-2

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- 3 x^{2} - 12 x - 12 = 0

x = - 2

Solution steps

- 3 x^{2} - 12 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 3 ) ( - 12 )}{2 ( - 3 )}

(- 12)^{2} - 4 (- 3) (- 12) = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 ( - 3 )}

x = \frac{- ( - 12 )}{2 ( - 3 )}

\frac{- ( - 12 )}{2 ( - 3 )} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

3 (x + 3) = 18

- 4 x - 8 > - 20

\frac{8}{3}

\frac{a ^{6} b ^{5} c ^{3}}{a ^{5} b ^{2} c ^{3}}

- \frac{5}{8} - (- \frac{4}{3})

What are the solutions to the equation -3x^2-12x-12=0 ?
The solutions to the equation -3x^2-12x-12=0 are x=-2
Find the zeros of -3x^2-12x-12=0
The zeros of -3x^2-12x-12=0 are x=-2