What is the answer to -1/(sqrt(-x^2+2x))=-2 ?

The answer to -1/(sqrt(-x^2+2x))=-2 is x=(2-sqrt(3))/2 ,x=(2+sqrt(3))/2

Solve for x: -1/(sqrt(-x^2+2x))=-2

The solution is x=(2-sqrt(3))/2 ,x=(2+sqrt(3))/2

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- \frac{1}{- x ^{2} + 2 x} = - 2

x = \frac{2 - 3}{2}, x = \frac{2 + 3}{2}

Decimal Notation

x = 0.13397 \dots, x = 1.86602 \dots

Solution steps

- \frac{1}{- x ^{2} + 2 x} = - 2

Multiply both sides by

- x^{2} + 2 x

- \frac{1}{- x ^{2} + 2 x} - x^{2} + 2 x = - 2 - x^{2} + 2 x

Simplify

- 1 = - 2 - x^{2} + 2 x

Switch sides

- 2 - x^{2} + 2 x = - 1

Divide both sides by

- 2

- x^{2} + 2 x = \frac{1}{2}

Square both sides:

- x^{2} + 2 x = \frac{1}{4}

- x^{2} + 2 x = \frac{1}{4}

Solve

- x^{2} + 2 x = \frac{1}{4} : x = \frac{2 - 3}{2}, x = \frac{2 + 3}{2}

x = \frac{2 - 3}{2}, x = \frac{2 + 3}{2}

Verify Solutions:

x = \frac{2 - 3}{2}

True

, x = \frac{2 + 3}{2}

True

The solutions are

x = \frac{2 - 3}{2}, x = \frac{2 + 3}{2}

90 = 53 Q^{0.18}

x^{\frac{1}{2}} = x

6 n + 1 = 7 n

43 - 2 y = y - 4

(3 x + 8) - 5 = 0

What is the answer to -1/(sqrt(-x^2+2x))=-2 ?
The answer to -1/(sqrt(-x^2+2x))=-2 is x=(2-sqrt(3))/2 ,x=(2+sqrt(3))/2
Solve for x: -1/(sqrt(-x^2+2x))=-2
The solution is x=(2-sqrt(3))/2 ,x=(2+sqrt(3))/2