What is the answer to solvefor x,y=sqrt(64-x^2) ?

The answer to solvefor x,y=sqrt(64-x^2) is x=sqrt(-y^2+64) {0<= y<= 8},x=-sqrt(-y^2+64) {0<= y<= 8}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y=sqrt(64-x^2)

solve for

x, y = 64 - x^{2}

x = - y^{2} + 64 {0 \leq y \leq 8}, x = - - y^{2} + 64 {0 \leq y \leq 8}

Solution steps

y = 64 - x^{2}

Square both sides:

y^{2} = 64 - x^{2}

y^{2} = 64 - x^{2}

Solve

y^{2} = 64 - x^{2} : x = - y^{2} + 64, x = - - y^{2} + 64

x = - y^{2} + 64, x = - - y^{2} + 64

Verify Solutions:

x = - y^{2} + 64 {0 \leq y \leq 8}, x = - - y^{2} + 64 {0 \leq y \leq 8}

The solutions are

x = - y^{2} + 64 {0 \leq y \leq 8}, x = - - y^{2} + 64 {0 \leq y \leq 8}

s, v = 2 a s

7 r + 9 = 35

2 u + 15 = 3

What is the answer to solvefor x,y=sqrt(64-x^2) ?
The answer to solvefor x,y=sqrt(64-x^2) is x=sqrt(-y^2+64) {0<= y<= 8},x=-sqrt(-y^2+64) {0<= y<= 8}