What is the answer to 1/(\sqrt[3]{2x-3)}=2 ?

The answer to 1/(\sqrt[3]{2x-3)}=2 is x= 25/16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/(\sqrt[3]{2x-3)}=2

\frac{1}{3 2 x - 3} = 2

x = \frac{25}{16}

Decimal

x = 1.5625

Solution steps

\frac{1}{3 2 x - 3} = 2

Multiply both sides by

3 2 x - 3

\frac{1}{3 2 x - 3} 3 2 x - 3 = 2 3 2 x - 3

Simplify

1 = 2 3 2 x - 3

Switch sides

2 3 2 x - 3 = 1

Divide both sides by

2

3 2 x - 3 = \frac{1}{2}

Take both sides of the equation to the power of

3 : 2 x - 3 = \frac{1}{8}

2 x - 3 = \frac{1}{8}

Solve

2 x - 3 = \frac{1}{8} : x = \frac{25}{16}

x = \frac{25}{16}

Verify Solutions:

x = \frac{25}{16}

True

The solution is

x = \frac{25}{16}

4 t + 8 = 2 t

3 9 w + 10 + 4 = 8

q + 10 = 20 - q

10 = x + 9 - 3

8 = x^{\frac{1}{2}}

What is the answer to 1/(\sqrt[3]{2x-3)}=2 ?
The answer to 1/(\sqrt[3]{2x-3)}=2 is x= 25/16
Solve for x: 1/(\sqrt[3]{2x-3)}=2
The solution is x= 25/16