What is the answer to 5=sqrt((4-1)^2+(y+1)^2) ?

The answer to 5=sqrt((4-1)^2+(y+1)^2) is y=3,y=-5

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5=sqrt((4-1)^2+(y+1)^2)

5 = (4 - 1)^{2} + (y + 1)^{2}

y = 3, y = - 5

Solution steps

5 = (4 - 1)^{2} + (y + 1)^{2}

Square both sides:

25 = y^{2} + 2 y + 10

25 = y^{2} + 2 y + 10

Solve

25 = y^{2} + 2 y + 10 : y = 3, y = - 5

y = 3, y = - 5

Verify Solutions:

y = 3

True

, y = - 5

True

The solutions are

y = 3, y = - 5

x + 2 - 3 x = 0

\frac{2}{3 x ^{\frac{1}{3}}} - 2 = 0

2.19 = 0.4336 \cdot X^{0.5664}

x + (x^{0.1}) = 100

v - 4 = 34 - v

What is the answer to 5=sqrt((4-1)^2+(y+1)^2) ?
The answer to 5=sqrt((4-1)^2+(y+1)^2) is y=3,y=-5
Solve for y: 5=sqrt((4-1)^2+(y+1)^2)
The solution is y=3,y=-5