What is the answer to 2x-1-sqrt(4x-2)=0 ?

The answer to 2x-1-sqrt(4x-2)=0 is x= 3/2 ,x= 1/2

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2x-1-sqrt(4x-2)=0

2 x - 1 - 4 x - 2 = 0

x = \frac{3}{2}, x = \frac{1}{2}

Decimal Notation

x = 1.5, x = 0.5

Solution steps

2 x - 1 - 4 x - 2 = 0

Remove square roots

4 x - 2 = 4 x^{2} - 4 x + 1

Solve

4 x - 2 = 4 x^{2} - 4 x + 1 : x = \frac{3}{2}, x = \frac{1}{2}

x = \frac{3}{2}, x = \frac{1}{2}

Verify Solutions:

x = \frac{3}{2}

True

, x = \frac{1}{2}

True

The solutions are

x = \frac{3}{2}, x = \frac{1}{2}

15 - 17 x = x + 9

1 - 16 x^{2} = 0

\frac{ψ}{ψ ^{2} + 1} = 1 - ψ

55 = \frac{143}{1 x}

What is the answer to 2x-1-sqrt(4x-2)=0 ?
The answer to 2x-1-sqrt(4x-2)=0 is x= 3/2 ,x= 1/2
Solve for x: 2x-1-sqrt(4x-2)=0
The solution is x= 3/2 ,x= 1/2