What is the answer to solvefor y,2x^2=-sqrt(2y) ?

The answer to solvefor y,2x^2=-sqrt(2y) is y=2x^4 {x=0}

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solvefor y,2x^2=-sqrt(2y)

solve for

y, 2 x^{2} = - 2 y

y = 2 x^{4} {x = 0}

Solution steps

2 x^{2} = - 2 y

Square both sides:

4 x^{4} = 2 y

4 x^{4} = 2 y

Solve

4 x^{4} = 2 y : y = 2 x^{4}

y = 2 x^{4}

Verify Solutions:

y = 2 x^{4} {x = 0}

The solution is

y = 2 x^{4} {x = 0}

19 - 2 x = x + 8

4 x^{2} - 4 x + 1 = 3

\frac{2000 ( 0.8 )}{x ^{0.2}} = 1500

x + 7 = x - 5 + 2

What is the answer to solvefor y,2x^2=-sqrt(2y) ?
The answer to solvefor y,2x^2=-sqrt(2y) is y=2x^4 {x=0}