What are the solutions to the equation 46-46x=(7x+3)(x-1) ?

The solutions to the equation 46-46x=(7x+3)(x-1) are x=1,x=-7

Find the zeros of 46-46x=(7x+3)(x-1)

The zeros of 46-46x=(7x+3)(x-1) are x=1,x=-7

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46 - 46 x = (7 x + 3) (x - 1)

x = 1, x = - 7

Solution steps

46 - 46 x = (7 x + 3) (x - 1)

Expand

(7 x + 3) (x - 1) : 7 x^{2} - 4 x - 3

46 - 46 x = 7 x^{2} - 4 x - 3

Switch sides

7 x^{2} - 4 x - 3 = 46 - 46 x

Move

46 x

to the left side

7 x^{2} + 42 x - 3 = 46

Move

46

to the left side

7 x^{2} + 42 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 42 \pm 4 2 ^{2} - 4 \cdot 7 ( - 49 )}{2 \cdot 7}

4 2^{2} - 4 \cdot 7 (- 49) = 56

x_{1, 2} = \frac{- 42 \pm 56}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 42 + 56}{2 \cdot 7}, x_{2} = \frac{- 42 - 56}{2 \cdot 7}

x = \frac{- 42 + 56}{2 \cdot 7} : 1

x = \frac{- 42 - 56}{2 \cdot 7} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

- 2 ∣ x - 3 ∣ < - 18

\frac{1}{2 π ( 5950 ) ( 1 \cdot 1 0 ^{- 6} )}

(\frac{z ^{4}}{6 ^{2}})^{- 3}

- \frac{2}{7} \cdot 3

5 m^{2} n^{3} - 20 m n^{4}

What are the solutions to the equation 46-46x=(7x+3)(x-1) ?
The solutions to the equation 46-46x=(7x+3)(x-1) are x=1,x=-7
Find the zeros of 46-46x=(7x+3)(x-1)
The zeros of 46-46x=(7x+3)(x-1) are x=1,x=-7