What is the answer to (-sqrt(10+n^2))/2 =n ?

The answer to (-sqrt(10+n^2))/2 =n is n=-sqrt(10/3)

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(-sqrt(10+n^2))/2 =n

\frac{- 10 + n ^{2}}{2} = n

n = - \frac{10}{3}

Decimal Notation

n = - 1.82574 \dots

Solution steps

\frac{- 10 + n ^{2}}{2} = n

Multiply both sides by

2

\frac{- 10 + n ^{2}}{2} \cdot 2 = n \cdot 2

Simplify

- 10 + n^{2} = n \cdot 2

Square both sides:

10 + n^{2} = 4 n^{2}

10 + n^{2} = 4 n^{2}

Solve

10 + n^{2} = 4 n^{2} : n = \frac{10}{3}, n = - \frac{10}{3}

n = \frac{10}{3}, n = - \frac{10}{3}

Verify Solutions:

n = \frac{10}{3}

False

, n = - \frac{10}{3}

True

The solution is

n = - \frac{10}{3}

x, x + 9 - 4 = 1

1438 = 2 π \frac{l}{9.8}

17 + y + y = 19

What is the answer to (-sqrt(10+n^2))/2 =n ?
The answer to (-sqrt(10+n^2))/2 =n is n=-sqrt(10/3)
Solve for n: (-sqrt(10+n^2))/2 =n
The solution is n=-sqrt(10/3)