What is the answer to x^2+3x-sqrt(x^2+3x-1)-7=0 ?

The answer to x^2+3x-sqrt(x^2+3x-1)-7=0 is x=2,x=-5

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x^2+3x-sqrt(x^2+3x-1)-7=0

x^{2} + 3 x - x^{2} + 3 x - 1 - 7 = 0

x = 2, x = - 5

Solution steps

x^{2} + 3 x - x^{2} + 3 x - 1 - 7 = 0

Remove square roots

x^{2} + 3 x - 1 = x^{4} + 6 x^{3} - 5 x^{2} - 42 x + 49

Solve

x^{2} + 3 x - 1 = x^{4} + 6 x^{3} - 5 x^{2} - 42 x + 49 : x = 2, x = - 5, x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

x = 2, x = - 5, x = \frac{- 3 + 29}{2}, x = \frac{- 3 - 29}{2}

Verify Solutions:

x = 2

True

, x = - 5

True

, x = \frac{- 3 + 29}{2}

False

, x = \frac{- 3 - 29}{2}

False

The solutions are

x = 2, x = - 5

x + 10 + x + 19 = - 1

(x - 5)^{\frac{3}{2}} = 64

5 - 4 x + 5 = x

x^{- 0.029} + 1.044932 = 0

5 7 + 3 x = 10

What is the answer to x^2+3x-sqrt(x^2+3x-1)-7=0 ?
The answer to x^2+3x-sqrt(x^2+3x-1)-7=0 is x=2,x=-5
Solve for x: x^2+3x-sqrt(x^2+3x-1)-7=0
The solution is x=2,x=-5