What is the answer to (1-3x)^2=(sqrt(x+17))^2 ?

The answer to (1-3x)^2=(sqrt(x+17))^2 is x= 16/9 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1-3x)^2=(sqrt(x+17))^2

(1 - 3 x)^{2} = (x + 17)^{2}

x = \frac{16}{9}, x = - 1

Decimal Notation

x = 1.77777 \dots, x = - 1

Solution steps

(1 - 3 x)^{2} = (x + 17)^{2}

Move

(x + 17)^{2}

to the left side

(1 - 3 x)^{2} - (x + 17)^{2} = 0

Factor

(1 - 3 x)^{2} - (x + 17)^{2} : (1 - 3 x + x + 17) (1 - 3 x - x + 17)

(1 - 3 x + x + 17) (1 - 3 x - x + 17) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

1 - 3 x + x + 17 = 0 or 1 - 3 x - x + 17 = 0

Solve

1 - 3 x + x + 17 = 0 : x = \frac{16}{9}

Solve

1 - 3 x - x + 17 = 0 : x = - 1

x = \frac{16}{9}, x = - 1

Verify Solutions:

x = \frac{16}{9}

True

, x = - 1

True

The solutions are

x = \frac{16}{9}, x = - 1

500 = 3 x + 9 x + 150

4.37 = 0.00051 \cdot M^{0.554}

\frac{2 x - 3}{x - 1} = x

4 x + 5 - x - 4 = 2

What is the answer to (1-3x)^2=(sqrt(x+17))^2 ?
The answer to (1-3x)^2=(sqrt(x+17))^2 is x= 16/9 ,x=-1
Solve for x: (1-3x)^2=(sqrt(x+17))^2
The solution is x= 16/9 ,x=-1