What is the answer to x^2+(\sqrt[3]{x^2})^2=1 ?

The answer to x^2+(\sqrt[3]{x^2})^2=1 is x=sqrt((4.3016E15)/(1.0E16)),x=-sqrt((4.3016E15)/(1.0E16))

Solve for x: x^2+(\sqrt[3]{x^2})^2=1

The solution is x=sqrt((4.3016E15)/(1.0E16)),x=-sqrt((4.3016E15)/(1.0E16))

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x = \frac{4.3016 E 15}{1.0 E 16}, x = - \frac{4.3016 E 15}{1.0 E 16}

Decimal Notation

x = 0.65586 \dots, x = - 0.65586 \dots

Solution steps

Expand

x^{2} + (x^{2})^{\frac{2}{3}} = 1

Remove roots

x^{4} = 1 - 3 x^{2} + 3 x^{4} - x^{6}

Solve

x^{4} = 1 - 3 x^{2} + 3 x^{4} - x^{6} : x = \frac{4.3016 E 15}{1.0 E 16}, x = - \frac{4.3016 E 15}{1.0 E 16}

x = \frac{4.3016 E 15}{1.0 E 16}, x = - \frac{4.3016 E 15}{1.0 E 16}

Verify Solutions:

x = \frac{4.3016 E 15}{1.0 E 16}

True

, x = - \frac{4.3016 E 15}{1.0 E 16}

True

The solutions are

x = \frac{4.3016 E 15}{1.0 E 16}, x = - \frac{4.3016 E 15}{1.0 E 16}

36 + d^{2} = 0

\frac{0.18}{n} = 0.001

x - 8 - 6 x = 0

x^{2} - 64 = 6

R = 2 3 R

What is the answer to x^2+(\sqrt[3]{x^2})^2=1 ?
The answer to x^2+(\sqrt[3]{x^2})^2=1 is x=sqrt((4.3016E15)/(1.0E16)),x=-sqrt((4.3016E15)/(1.0E16))
Solve for x: x^2+(\sqrt[3]{x^2})^2=1
The solution is x=sqrt((4.3016E15)/(1.0E16)),x=-sqrt((4.3016E15)/(1.0E16))