What is the answer to solvefor y,x=sqrt(3y-4) ?

The answer to solvefor y,x=sqrt(3y-4) is y=(x^2+4)/3 {x>= 0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor y,x=sqrt(3y-4)

solve for

y, x = 3 y - 4

y = \frac{x ^{2} + 4}{3} {x \geq 0}

Solution steps

x = 3 y - 4

Square both sides:

x^{2} = 3 y - 4

x^{2} = 3 y - 4

Solve

x^{2} = 3 y - 4 : y = \frac{x ^{2} + 4}{3}

y = \frac{x ^{2} + 4}{3}

Verify Solutions:

y = \frac{x ^{2} + 4}{3} {x \geq 0}

The solution is

y = \frac{x ^{2} + 4}{3} {x \geq 0}

2 w + 18 + 1 = 5

- x + 5 = x + 1

1 = 3 x + 18 - 2

4 x - 3 = 2 + 2 x + 5

(x + 3) - 4 x + 3 - 5 = 0

What is the answer to solvefor y,x=sqrt(3y-4) ?
The answer to solvefor y,x=sqrt(3y-4) is y=(x^2+4)/3 {x>= 0}