What is the answer to x+\sqrt[4]{4-(x^4-13)}=3 ?

The answer to x+\sqrt[4]{4-(x^4-13)}=3 is x=1,x=2

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x+\sqrt[4]{4-(x^4-13)}=3

x = 1, x = 2

Solution steps

Remove roots

- x^{4} + 17 = 81 - 108 x + 54 x^{2} - 12 x^{3} + x^{4}

Solve

- x^{4} + 17 = 81 - 108 x + 54 x^{2} - 12 x^{3} + x^{4} : x = 1, x = 2

x = 1, x = 2

Verify Solutions:

x = 1

True

, x = 2

True

The solutions are

x = 1, x = 2

C^{13.8} = \frac{13 !}{8 ! ( 13 - 8 ) !}

4 x^{2} = 8

x + 9 = x^{2} + 4 x + 4

x = 1 - \frac{1}{x + 1}

What is the answer to x+\sqrt[4]{4-(x^4-13)}=3 ?
The answer to x+\sqrt[4]{4-(x^4-13)}=3 is x=1,x=2
Solve for x: x+\sqrt[4]{4-(x^4-13)}=3
The solution is x=1,x=2