What are the solutions to the equation 2p^2-32=0 ?

The solutions to the equation 2p^2-32=0 are p=4,p=-4

Find the zeros of 2p^2-32=0

The zeros of 2p^2-32=0 are p=4,p=-4

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2 p^{2} - 32 = 0

p = 4, p = - 4

Solution steps

2 p^{2} - 32 = 0

Move

32

to the right side

2 p^{2} = 32

Divide both sides by

2

p^{2} = 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 16, p = - 16

16 = 4

- 16 = - 4

p = 4, p = - 4

x^{2} + 2 x - 99

6 x + 5 = 20

(1 + i) (3 - 5 i)

x^{2} - 3 x + 4 = 4

7 x^{2} - 14 x

What are the solutions to the equation 2p^2-32=0 ?
The solutions to the equation 2p^2-32=0 are p=4,p=-4
Find the zeros of 2p^2-32=0
The zeros of 2p^2-32=0 are p=4,p=-4