What is the answer to 4=4-sqrt((2x^0)/3) ?

The answer to 4=4-sqrt((2x^0)/3) is No Solution for x\in\mathbb{R}

Solve for x: 4=4-sqrt((2x^0)/3)

The solution is No Solution for x\in\mathbb{R}

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4 = 4 - \frac{2 x ^{0}}{3}

No Solution for x \in R

Solution steps

4 = 4 - \frac{2 x ^{0}}{3}

Subtract

4

from both sides

4 - 4 = 4 - \frac{2 x ^{0}}{3} - 4

Simplify

0 = - \frac{2 x ^{0}}{3}

Move

\frac{2 x ^{0}}{3}

to the left side

\frac{2 x ^{0}}{3} = 0

Square both sides:

\frac{2}{3} = 0

\frac{2}{3} = 0

The sides are not equal

No Solution for x \in R

3 x + 4 = 3 x + 4

x^{\frac{5}{2}} = 0

x^{\frac{5}{2}} = 3

x^{\frac{5}{2}} = 4

2 a^{2} - 3 = - \frac{a - 3}{2}

What is the answer to 4=4-sqrt((2x^0)/3) ?
The answer to 4=4-sqrt((2x^0)/3) is No Solution for x\in\mathbb{R}
Solve for x: 4=4-sqrt((2x^0)/3)
The solution is No Solution for x\in\mathbb{R}