What is the answer to solvefor x,2(2xy)=sqrt(4xy) ?

The answer to solvefor x,2(2xy)=sqrt(4xy) is x=0,x= 1/(4y) {y 0}

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solvefor x,2(2xy)=sqrt(4xy)

solve for

x, 2 (2 x y) = 4 x y

x = 0, x = \frac{1}{4 y} {y < 0 or y > 0}

Solution steps

2 (2 x y) = 4 x y

Expand

2 \cdot 2 x y : 4 x y

4 x y = 4 x y

Square both sides:

16 x^{2} y^{2} = 4 x y

16 x^{2} y^{2} = 4 x y

Solve

16 x^{2} y^{2} = 4 x y : x = 0, x = \frac{1}{4 y}

x = 0, x = \frac{1}{4 y}

Verify Solutions:

x = 0

True

, x = \frac{1}{4 y} {y < 0 or y > 0}

The solutions are

x = 0, x = \frac{1}{4 y} {y < 0 or y > 0}

x, x + 2 = x - 1

y^{\frac{2}{3}} - \frac{1}{36} = 0

x, 6 + 3 x - 4 = 24

3 + - x^{2} + 4 = x^{2} 11

(2 x - 7)^{\frac{3}{4}} + 6 = 14

What is the answer to solvefor x,2(2xy)=sqrt(4xy) ?
The answer to solvefor x,2(2xy)=sqrt(4xy) is x=0,x= 1/(4y) {y<0\lor y>0}