What is the answer to 0=(2x-sqrt(x^2+1)) ?

The answer to 0=(2x-sqrt(x^2+1)) is x= 1/(sqrt(3))

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0=(2x-sqrt(x^2+1))

0 = (2 x - x^{2} + 1)

x = \frac{1}{3}

Decimal Notation

x = 0.57735 \dots

Solution steps

0 = (2 x - x^{2} + 1)

Remove square roots

4 x^{2} = x^{2} + 1

Solve

4 x^{2} = x^{2} + 1 : x = \frac{1}{3}, x = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

, x = - \frac{1}{3}

False

The solution is

x = \frac{1}{3}

- - y + 25 + 5 = - y

3 n + 10 = n + 4

1 = u^{0.1} + u^{0.4} + u^{0.7}

- x - x^{2} - 2 x = 0

4 + 21 e^{- 0.2} = 8

What is the answer to 0=(2x-sqrt(x^2+1)) ?
The answer to 0=(2x-sqrt(x^2+1)) is x= 1/(sqrt(3))
Solve for x: 0=(2x-sqrt(x^2+1))
The solution is x= 1/(sqrt(3))