What is the answer to solvefor y,x=-1+sqrt(y) ?

The answer to solvefor y,x=-1+sqrt(y) is y=x^2+2x+1 {x>=-1}

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solvefor y,x=-1+sqrt(y)

solve for

y, x = - 1 + y

y = x^{2} + 2 x + 1 {x \geq - 1}

Solution steps

x = - 1 + y

Switch sides

- 1 + y = x

Move

1

to the right side

y = x + 1

Square both sides:

y = x^{2} + 2 x + 1

y = x^{2} + 2 x + 1

Verify Solutions:

y = x^{2} + 2 x + 1 {x \geq - 1}

The solution is

y = x^{2} + 2 x + 1 {x \geq - 1}

x, 9 = 6 x - 3

30 - 4 x + 4 x^{2} - 60 x + 330 = 36

2.7 = 4.27 + x^{8.9}

What is the answer to solvefor y,x=-1+sqrt(y) ?
The answer to solvefor y,x=-1+sqrt(y) is y=x^2+2x+1 {x>=-1}