What is the answer to solvefor y,f=2\sqrt[3]{y}+5 ?

The answer to solvefor y,f=2\sqrt[3]{y}+5 is y=(f^3)/8-(15f^2)/8+(75f)/8-125/8

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solvefor y,f=2\sqrt[3]{y}+5

solve for

y = \frac{f ^{3}}{8} - \frac{15 f ^{2}}{8} + \frac{75 f}{8} - \frac{125}{8}

Solution steps

Switch sides

Move

5

to the right side

Divide both sides by

2

Take both sides of the equation to the power of

3 : y = \frac{f ^{3}}{8} - \frac{15 f ^{2}}{8} + \frac{75 f}{8} - \frac{125}{8}

y = \frac{f ^{3}}{8} - \frac{15 f ^{2}}{8} + \frac{75 f}{8} - \frac{125}{8}

Verify Solutions:

y = \frac{f ^{3}}{8} - \frac{15 f ^{2}}{8} + \frac{75 f}{8} - \frac{125}{8}

True

The solution is

y = \frac{f ^{3}}{8} - \frac{15 f ^{2}}{8} + \frac{75 f}{8} - \frac{125}{8}

1 + (x - 2)^{\frac{2}{3}} = 0

10 x + 100 + 10 = x

X = \frac{13}{2}

m + 8 - 1 = 6

What is the answer to solvefor y,f=2\sqrt[3]{y}+5 ?
The answer to solvefor y,f=2\sqrt[3]{y}+5 is y=(f^3)/8-(15f^2)/8+(75f)/8-125/8