What is the answer to solvefor x,y=sqrt(36-x^2) ?

The answer to solvefor x,y=sqrt(36-x^2) is x=sqrt(-y^2+36) {0<= y<= 6},x=-sqrt(-y^2+36) {0<= y<= 6}

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solvefor x,y=sqrt(36-x^2)

solve for

x, y = 36 - x^{2}

x = - y^{2} + 36 {0 \leq y \leq 6}, x = - - y^{2} + 36 {0 \leq y \leq 6}

Solution steps

y = 36 - x^{2}

Square both sides:

y^{2} = 36 - x^{2}

y^{2} = 36 - x^{2}

Solve

y^{2} = 36 - x^{2} : x = - y^{2} + 36, x = - - y^{2} + 36

x = - y^{2} + 36, x = - - y^{2} + 36

Verify Solutions:

x = - y^{2} + 36 {0 \leq y \leq 6}, x = - - y^{2} + 36 {0 \leq y \leq 6}

The solutions are

x = - y^{2} + 36 {0 \leq y \leq 6}, x = - - y^{2} + 36 {0 \leq y \leq 6}

8 x + 16 + 4 = x

5 - x = 3 - x

- (8 x)^{\frac{6}{5}} - 4 = - 68

2 x + 31 = 0

- 40.3 - 9.81 x^{10.02842} = - 138

What is the answer to solvefor x,y=sqrt(36-x^2) ?
The answer to solvefor x,y=sqrt(36-x^2) is x=sqrt(-y^2+36) {0<= y<= 6},x=-sqrt(-y^2+36) {0<= y<= 6}