What is the answer to solvefor x,g(2x)=sqrt(2x) ?

The answer to solvefor x,g(2x)=sqrt(2x) is x=0,x= 1/(2g^2) {g 0}

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solvefor x,g(2x)=sqrt(2x)

solve for

x, g (2 x) = 2 x

x = 0, x = \frac{1}{2 g ^{2}} {g < 0 or g > 0}

Solution steps

g (2 x) = 2 x

Square both sides:

4 x^{2} g^{2} = 2 x

4 x^{2} g^{2} = 2 x

Solve

4 x^{2} g^{2} = 2 x : x = 0, x = \frac{1}{2 g ^{2}}

x = 0, x = \frac{1}{2 g ^{2}}

Verify Solutions:

x = 0

True

, x = \frac{1}{2 g ^{2}} {g < 0 or g > 0}

The solutions are

x = 0, x = \frac{1}{2 g ^{2}} {g < 0 or g > 0}

x^{2} + 7 + x - 1 = 0

2 + b = 10

6 = 2 x

3.8 x^{- 0.2} - 2.9 = 0

4 a = 2 a - 2

What is the answer to solvefor x,g(2x)=sqrt(2x) ?
The answer to solvefor x,g(2x)=sqrt(2x) is x=0,x= 1/(2g^2) {g<0\lor g>0}