What is the answer to -3/2 =sqrt(x^2+2x+3) ?

The answer to -3/2 =sqrt(x^2+2x+3) is No Solution for x\in\mathbb{R}

Solve for x: -3/2 =sqrt(x^2+2x+3)

The solution is No Solution for x\in\mathbb{R}

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Popular >

- \frac{3}{2} = x^{2} + 2 x + 3

No Solution for x \in R

Solution steps

- \frac{3}{2} = x^{2} + 2 x + 3

Square both sides:

\frac{9}{4} = x^{2} + 2 x + 3

\frac{9}{4} = x^{2} + 2 x + 3

Solve

\frac{9}{4} = x^{2} + 2 x + 3 : x = - \frac{1}{2}, x = - \frac{3}{2}

x = - \frac{1}{2}, x = - \frac{3}{2}

Verify Solutions:

x = - \frac{1}{2}

False

, x = - \frac{3}{2}

False

The solution is

No Solution for x \in R

- 2 y - 4 + 2 y + 8 = 2

2 x + 3 - 4 = 0

(3 - x) (3 + x) = 7

2 x + 4 - x - 3 = 2

What is the answer to -3/2 =sqrt(x^2+2x+3) ?
The answer to -3/2 =sqrt(x^2+2x+3) is No Solution for x\in\mathbb{R}
Solve for x: -3/2 =sqrt(x^2+2x+3)
The solution is No Solution for x\in\mathbb{R}