What is the answer to 5=sqrt((5-0)^2+(2-X)^2) ?

The answer to 5=sqrt((5-0)^2+(2-X)^2) is X=2

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5=sqrt((5-0)^2+(2-X)^2)

5 = (5 - 0)^{2} + (2 - X)^{2}

X = 2

Solution steps

5 = (5 - 0)^{2} + (2 - X)^{2}

Square both sides:

25 = X^{2} - 4 X + 29

25 = X^{2} - 4 X + 29

Solve

25 = X^{2} - 4 X + 29 : X = 2

X = 2

Verify Solutions:

X = 2

True

The solution is

X = 2

x + 7 - 2 = 0

6 = \frac{t}{\frac{2}{9}}

3 - x = 4 x

11.68 = \frac{S}{12.6}

What is the answer to 5=sqrt((5-0)^2+(2-X)^2) ?
The answer to 5=sqrt((5-0)^2+(2-X)^2) is X=2
Solve for X: 5=sqrt((5-0)^2+(2-X)^2)
The solution is X=2