What is the answer to sqrt(x)=sqrt(2)-x+1 ?

The answer to sqrt(x)=sqrt(2)-x+1 is x=(2sqrt(2)+3-sqrt(5+4\sqrt{2)})/2

Solve for x: sqrt(x)=sqrt(2)-x+1

The solution is x=(2sqrt(2)+3-sqrt(5+4\sqrt{2)})/2

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x = 2 - x + 1

x = \frac{2 2 + 3 - 5 + 4 2}{2}

Decimal Notation

x = 1.28197 \dots

Solution steps

x = 2 - x + 1

Square both sides:

x = x^{2} - 22 x - 2 x + 3 + 22

x = x^{2} - 22 x - 2 x + 3 + 22

Solve

x = x^{2} - 22 x - 2 x + 3 + 22 : x = \frac{2 2 + 3 + 5 + 4 2}{2}, x = \frac{2 2 + 3 - 5 + 4 2}{2}

x = \frac{2 2 + 3 + 5 + 4 2}{2}, x = \frac{2 2 + 3 - 5 + 4 2}{2}

Verify Solutions:

x = \frac{2 2 + 3 + 5 + 4 2}{2}

False

, x = \frac{2 2 + 3 - 5 + 4 2}{2}

True

The solution is

x = \frac{2 2 + 3 - 5 + 4 2}{2}

3 z + 25 + 6 = z + 5

(6 x + 21 + 3)^{2} = (x - 2)^{2}

x + 3 = 9 - x

150 \cdot 15 = 12 j

0 = x + 1 - 2

What is the answer to sqrt(x)=sqrt(2)-x+1 ?
The answer to sqrt(x)=sqrt(2)-x+1 is x=(2sqrt(2)+3-sqrt(5+4\sqrt{2)})/2
Solve for x: sqrt(x)=sqrt(2)-x+1
The solution is x=(2sqrt(2)+3-sqrt(5+4\sqrt{2)})/2