What is the answer to \sqrt[4]{6x^2-9}=0 ?

The answer to \sqrt[4]{6x^2-9}=0 is x=sqrt(3/2),x=-sqrt(3/2)

Solve for x: \sqrt[4]{6x^2-9}=0

The solution is x=sqrt(3/2),x=-sqrt(3/2)

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x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 1.22474 \dots, x = - 1.22474 \dots

Solution steps

Take both sides of the equation to the power of

4 : 6 x^{2} - 9 = 0

6 x^{2} - 9 = 0

Solve

6 x^{2} - 9 = 0 : x = \frac{3}{2}, x = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

Verify Solutions:

x = \frac{3}{2}

True

, x = - \frac{3}{2}

True

The solutions are

x = \frac{3}{2}, x = - \frac{3}{2}

z = - 1

5 + 4 x - 2 = 17

25 x - 20 = 1.5 1 - x^{2}

What is the answer to \sqrt[4]{6x^2-9}=0 ?
The answer to \sqrt[4]{6x^2-9}=0 is x=sqrt(3/2),x=-sqrt(3/2)
Solve for x: \sqrt[4]{6x^2-9}=0
The solution is x=sqrt(3/2),x=-sqrt(3/2)