What is (i-2)/(i-1) ?

The solution to (i-2)/(i-1) is 3/2+1/2 i

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simplify (i-2)/(i-1)

simplify

\frac{i - 2}{i - 1}

\frac{3}{2} + \frac{1}{2} i

Solution steps

\frac{i - 2}{i - 1}

Rewrite

i - 2

in standard complex form:

- 2 + i

Rewrite

i - 1

in standard complex form:

- 1 + i

= \frac{- 2 + i}{- 1 + i}

Multiply by the conjugate

\frac{- 1 - i}{- 1 - i}

= \frac{( - 2 + i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )}

Simplify

\frac{( - 2 + i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )} : \frac{3 + i}{2}

= \frac{3 + i}{2}

Rewrite in standard complex form:

\frac{3}{2} + \frac{1}{2} i

= \frac{3}{2} + \frac{1}{2} i

x y + 7 y - 3 x - 21

- 1 (1 + 7 x) - 6 (- 7 - x) = 36

3 x = 33

3 \leq x < 5

n^{2} + 13 n + 40 = 0