What is the answer to 1=x*sqrt(x^2+x^2)-x ?

The answer to 1=x*sqrt(x^2+x^2)-x is x=(1+sqrt(1+4\sqrt{2)})/(2sqrt(2))

Solve for x: 1=x*sqrt(x^2+x^2)-x

The solution is x=(1+sqrt(1+4\sqrt{2)})/(2sqrt(2))

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1 = x \cdot x^{2} + x^{2} - x

x = \frac{1 + 1 + 4 2}{2 2}

Decimal Notation

x = 1.26575 \dots

Solution steps

1 = x x^{2} + x^{2} - x

Remove square roots

1 + 2 x + x^{2} = 2 x^{4}

Solve

1 + 2 x + x^{2} = 2 x^{4} : x = \frac{1 + 1 + 4 2}{2 2}, x = \frac{1 - 1 + 4 2}{2 2}

x = \frac{1 + 1 + 4 2}{2 2}, x = \frac{1 - 1 + 4 2}{2 2}

Verify Solutions:

x = \frac{1 + 1 + 4 2}{2 2}

True

, x = \frac{1 - 1 + 4 2}{2 2}

False

The solution is

x = \frac{1 + 1 + 4 2}{2 2}

5 (25 x)^{\frac{4}{3}} = 3125

2 x + 6 - x - 4 = 1

\frac{2 x}{2 x ^{2} + 4} = 0

100 - 19 x - 1 = 9

30000 = p^{0.08 (10)}

What is the answer to 1=x*sqrt(x^2+x^2)-x ?
The answer to 1=x*sqrt(x^2+x^2)-x is x=(1+sqrt(1+4\sqrt{2)})/(2sqrt(2))
Solve for x: 1=x*sqrt(x^2+x^2)-x
The solution is x=(1+sqrt(1+4\sqrt{2)})/(2sqrt(2))