What are the solutions to the equation 0=x^2+3x-18 ?

The solutions to the equation 0=x^2+3x-18 are x=3,x=-6

Find the zeros of 0=x^2+3x-18

The zeros of 0=x^2+3x-18 are x=3,x=-6

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0 = x^{2} + 3 x - 18

x = 3, x = - 6

Solution steps

0 = x^{2} + 3 x - 18

Switch sides

x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 \cdot 1}, x_{2} = \frac{- 3 - 9}{2 \cdot 1}

x = \frac{- 3 + 9}{2 \cdot 1} : 3

x = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 3, x = - 6

(\frac{y}{3})^{- 10}

∣ 9 x ∣ < - 5

\frac{x ^{5} x ^{- 5}}{y ^{3} y ^{- 2}}

8^{- 2} \cdot a^{7}

x^{2} + x - 240 = 0

What are the solutions to the equation 0=x^2+3x-18 ?
The solutions to the equation 0=x^2+3x-18 are x=3,x=-6
Find the zeros of 0=x^2+3x-18
The zeros of 0=x^2+3x-18 are x=3,x=-6