What is the answer to (1+x)^{2/5}=2 ?

The answer to (1+x)^{2/5}=2 is x=4*2^{1/2}-1,x=-4*2^{1/2}-1

Solve for x: (1+x)^{2/5}=2

The solution is x=4*2^{1/2}-1,x=-4*2^{1/2}-1

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(1 + x)^{\frac{2}{5}} = 2

x = 4 \cdot 2^{\frac{1}{2}} - 1, x = - 4 \cdot 2^{\frac{1}{2}} - 1

Decimal Notation

x = 4.65685 \dots, x = - 6.65685 \dots

Solution steps

(1 + x)^{\frac{2}{5}} = 2

Take both sides of the equation to the power of

5 : (1 + x)^{2} = 32

(1 + x)^{2} = 32

Solve

(1 + x)^{2} = 32 : x = 4 \cdot 2^{\frac{1}{2}} - 1, x = - 4 \cdot 2^{\frac{1}{2}} - 1

x = 4 \cdot 2^{\frac{1}{2}} - 1, x = - 4 \cdot 2^{\frac{1}{2}} - 1

Verify Solutions:

x = 4 \cdot 2^{\frac{1}{2}} - 1

True

, x = - 4 \cdot 2^{\frac{1}{2}} - 1

True

The solutions are

x = 4 \cdot 2^{\frac{1}{2}} - 1, x = - 4 \cdot 2^{\frac{1}{2}} - 1

4 = x + 7

105 + 5 z - z^{2} = z + 9

x^{2} + b^{2} + x (1 - e) = x

x^{2} - 5 x - 2 = 3

22 - x = 2 + 3 x

What is the answer to (1+x)^{2/5}=2 ?
The answer to (1+x)^{2/5}=2 is x=4*2^{1/2}-1,x=-4*2^{1/2}-1
Solve for x: (1+x)^{2/5}=2
The solution is x=4*2^{1/2}-1,x=-4*2^{1/2}-1