What is the answer to a=sqrt(x^2-4) ?

The answer to a=sqrt(x^2-4) is x=sqrt(a^2+4) {a>= 0},x=-sqrt(a^2+4) {a>= 0}

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a=sqrt(x^2-4)

a = x^{2} - 4

x = a^{2} + 4 {a \geq 0}, x = - a^{2} + 4 {a \geq 0}

Solution steps

a = x^{2} - 4

Square both sides:

a^{2} = x^{2} - 4

a^{2} = x^{2} - 4

Solve

a^{2} = x^{2} - 4 : x = a^{2} + 4, x = - a^{2} + 4

x = a^{2} + 4, x = - a^{2} + 4

Verify Solutions:

x = a^{2} + 4 {a \geq 0}, x = - a^{2} + 4 {a \geq 0}

The solutions are

x = a^{2} + 4 {a \geq 0}, x = - a^{2} + 4 {a \geq 0}

4 x - 7 - 5 = 0

3 + x = - 1

10 x - x^{2} = 2 x + 1

y, x = y - 1 y - 1 3

x^{2.5} x^{2} - 2.5 x + 0.00025 = 0

What is the answer to a=sqrt(x^2-4) ?
The answer to a=sqrt(x^2-4) is x=sqrt(a^2+4) {a>= 0},x=-sqrt(a^2+4) {a>= 0}