What is the answer to (y+2)^{3/4}=2 ?

The answer to (y+2)^{3/4}=2 is y=2*2^{1/3}-2

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(y+2)^{3/4}=2

(y + 2)^{\frac{3}{4}} = 2

y = 2 \cdot 2^{\frac{1}{3}} - 2

Decimal Notation

y = 0.51984 \dots

Solution steps

(y + 2)^{\frac{3}{4}} = 2

Take both sides of the equation to the power of

4 : (y + 2)^{3} = 16

(y + 2)^{3} = 16

Solve

(y + 2)^{3} = 16 : y = 2 \cdot 2^{\frac{1}{3}} - 2

y = 2 \cdot 2^{\frac{1}{3}} - 2

Verify Solutions:

y = 2 \cdot 2^{\frac{1}{3}} - 2

True

The solution is

y = 2 \cdot 2^{\frac{1}{3}} - 2

n^{2} = n^{0.1}

y = \frac{2}{y}

\frac{1}{1 - x ^{2}} = 1.65

x, (x^{2} - 1) y = 1

1 + x + 1 = 4

What is the answer to (y+2)^{3/4}=2 ?
The answer to (y+2)^{3/4}=2 is y=2*2^{1/3}-2
Solve for y: (y+2)^{3/4}=2
The solution is y=2*2^{1/3}-2