What is the answer to 3x-1=sqrt(x+4) ?

The answer to 3x-1=sqrt(x+4) is x=(7+sqrt(157))/(18)

Solve for x: 3x-1=sqrt(x+4)

The solution is x=(7+sqrt(157))/(18)

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3 x - 1 = x + 4

x = \frac{7 + 157}{18}

Decimal Notation

x = 1.08499 \dots

Solution steps

3 x - 1 = x + 4

Square both sides:

9 x^{2} - 6 x + 1 = x + 4

9 x^{2} - 6 x + 1 = x + 4

Solve

9 x^{2} - 6 x + 1 = x + 4 : x = \frac{7 + 157}{18}, x = \frac{7 - 157}{18}

x = \frac{7 + 157}{18}, x = \frac{7 - 157}{18}

Verify Solutions:

x = \frac{7 + 157}{18}

True

, x = \frac{7 - 157}{18}

False

The solution is

x = \frac{7 + 157}{18}

2 x^{3} + 3 x^{2} + 3 x + 1 = 3

2 x + 2 x - 3 = 3

2 x - 9 = 5

3 = \frac{9 x}{2}

2 x - 9 = 9

What is the answer to 3x-1=sqrt(x+4) ?
The answer to 3x-1=sqrt(x+4) is x=(7+sqrt(157))/(18)
Solve for x: 3x-1=sqrt(x+4)
The solution is x=(7+sqrt(157))/(18)