What are the solutions to the equation x^2-4x-224=0 ?

The solutions to the equation x^2-4x-224=0 are x=2(1+sqrt(57)),x=2(1-sqrt(57))

Find the zeros of x^2-4x-224=0

The zeros of x^2-4x-224=0 are x=2(1+sqrt(57)),x=2(1-sqrt(57))

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x^{2} - 4 x - 224 = 0

x = 2 (1 + 57), x = 2 (1 - 57)

Decimal Notation

x = 17.09966 \dots, x = - 13.09966 \dots

Solution steps

x^{2} - 4 x - 224 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 224 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 224) = 457

x_{1, 2} = \frac{- ( - 4 ) \pm 4 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 57}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 57}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 57}{2 \cdot 1} : 2 (1 + 57)

x = \frac{- ( - 4 ) - 4 57}{2 \cdot 1} : 2 (1 - 57)

The solutions to the quadratic equation are:

x = 2 (1 + 57), x = 2 (1 - 57)

- \frac{1}{2} x - 7 = 18

n^{2} - 30 n + 56

- 3 (\frac{3}{2})^{0}

- 5160 - 10160

r - 6 \geq 45

What are the solutions to the equation x^2-4x-224=0 ?
The solutions to the equation x^2-4x-224=0 are x=2(1+sqrt(57)),x=2(1-sqrt(57))
Find the zeros of x^2-4x-224=0
The zeros of x^2-4x-224=0 are x=2(1+sqrt(57)),x=2(1-sqrt(57))