What is the answer to sqrt(x^2+(\sqrt{3x))^2}=8 ?

The answer to sqrt(x^2+(\sqrt{3x))^2}=8 is x=(-3+sqrt(265))/2

Solve for x: sqrt(x^2+(\sqrt{3x))^2}=8

The solution is x=(-3+sqrt(265))/2

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x^{2} + (3 x)^{2} = 8

x = \frac{- 3 + 265}{2}

Decimal Notation

x = 6.63941 \dots

Solution steps

x^{2} + (3 x)^{2} = 8

Square both sides:

x^{2} + 3 x = 64

x^{2} + 3 x = 64

Solve

x^{2} + 3 x = 64 : x = \frac{- 3 + 265}{2}, x = \frac{- 3 - 265}{2}

x = \frac{- 3 + 265}{2}, x = \frac{- 3 - 265}{2}

Verify Solutions:

x = \frac{- 3 + 265}{2}

True

, x = \frac{- 3 - 265}{2}

False

The solution is

x = \frac{- 3 + 265}{2}

x = x - 1

5 x^{2} = 8 x

\frac{5}{x - 4} - 2 x - 4 + 3 = 0

(6 x + 1)^{\frac{1}{2}} = 5

16 r + 8 = 12

What is the answer to sqrt(x^2+(\sqrt{3x))^2}=8 ?
The answer to sqrt(x^2+(\sqrt{3x))^2}=8 is x=(-3+sqrt(265))/2
Solve for x: sqrt(x^2+(\sqrt{3x))^2}=8
The solution is x=(-3+sqrt(265))/2