What is the answer to solvefor y,x=sqrt(y+4) ?

The answer to solvefor y,x=sqrt(y+4) is y=x^2-4 {x>= 0}

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solvefor y,x=sqrt(y+4)

solve for

y, x = y + 4

y = x^{2} - 4 {x \geq 0}

Solution steps

x = y + 4

Square both sides:

x^{2} = y + 4

x^{2} = y + 4

Solve

x^{2} = y + 4 : y = x^{2} - 4

y = x^{2} - 4

Verify Solutions:

y = x^{2} - 4 {x \geq 0}

The solution is

y = x^{2} - 4 {x \geq 0}

v, 2 v = t

v = 9

2 x + 3 + x + 6 = 2

v = 2

6 X = 36 X^{2} + 2 X - 10

What is the answer to solvefor y,x=sqrt(y+4) ?
The answer to solvefor y,x=sqrt(y+4) is y=x^2-4 {x>= 0}