What is the answer to sqrt(2x^2+3x-1)=sqrt(5-x) ?

The answer to sqrt(2x^2+3x-1)=sqrt(5-x) is x=1,x=-3

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sqrt(2x^2+3x-1)=sqrt(5-x)

2 x^{2} + 3 x - 1 = 5 - x

x = 1, x = - 3

Solution steps

2 x^{2} + 3 x - 1 = 5 - x

Square both sides:

2 x^{2} + 3 x - 1 = 5 - x

2 x^{2} + 3 x - 1 = 5 - x

Solve

2 x^{2} + 3 x - 1 = 5 - x : x = 1, x = - 3

x = 1, x = - 3

Verify Solutions:

x = 1

True

, x = - 3

True

The solutions are

x = 1, x = - 3

15 x = 5 x

0 = 96 q - 4 q^{\frac{3}{2}}

x = - 5 - 6 x

x + 1 + 5 = x

5 x - 3 = 2

What is the answer to sqrt(2x^2+3x-1)=sqrt(5-x) ?
The answer to sqrt(2x^2+3x-1)=sqrt(5-x) is x=1,x=-3
Solve for x: sqrt(2x^2+3x-1)=sqrt(5-x)
The solution is x=1,x=-3