What is the answer to solvefor x,2x+y+2sqrt(xy)=34 ?

The answer to solvefor x,2x+y+2sqrt(xy)=34 is x=(34+sqrt(y(-y+68)))/2 ,x=(34-sqrt(y(-y+68)))/2

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solvefor x,2x+y+2sqrt(xy)=34

solve for

x, 2 x + y + 2 x y = 34

x = \frac{34 + y ( - y + 68 )}{2}, x = \frac{34 - y ( - y + 68 )}{2}

Solution steps

2 x + y + 2 x y = 34

Remove square roots

4 x y = 4 x y - 68 y + y^{2} - 136 x + 4 x^{2} + 1156

Solve

4 x y = 4 x y - 68 y + y^{2} - 136 x + 4 x^{2} + 1156 : x = \frac{34 + y ( - y + 68 )}{2}, x = \frac{34 - y ( - y + 68 )}{2}

x = \frac{34 + y ( - y + 68 )}{2}, x = \frac{34 - y ( - y + 68 )}{2}

Verify Solutions:

x = \frac{34 + y ( - y + 68 )}{2}

True

, x = \frac{34 - y ( - y + 68 )}{2}

True

The solutions are

x = \frac{34 + y ( - y + 68 )}{2}, x = \frac{34 - y ( - y + 68 )}{2}

x^{2} + 4 x + 4 = 4 x - 3

x^{\frac{1}{4}} = 0

v - 5 = - 5 v + 39

x^{\frac{1}{4}} = 9

\frac{x}{x - 3} = x - 2

What is the answer to solvefor x,2x+y+2sqrt(xy)=34 ?
The answer to solvefor x,2x+y+2sqrt(xy)=34 is x=(34+sqrt(y(-y+68)))/2 ,x=(34-sqrt(y(-y+68)))/2