What is the answer to 4=sqrt((x-1)^2)+(3-1)^2 ?

The answer to 4=sqrt((x-1)^2)+(3-1)^2 is x=1

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4=sqrt((x-1)^2)+(3-1)^2

4 = (x - 1)^{2} + (3 - 1)^{2}

x = 1

Solution steps

4 = (x - 1)^{2} + (3 - 1)^{2}

Expand

(x - 1)^{2} + (3 - 1)^{2} : x^{2} - 2 x + 1 + 4

4 = x^{2} - 2 x + 1 + 4

Subtract

4

from both sides

4 - 4 = x^{2} - 2 x + 1 + 4 - 4

Simplify

0 = x^{2} - 2 x + 1

Switch sides

x^{2} - 2 x + 1 = 0

Square both sides:

x^{2} - 2 x + 1 = 0

x^{2} - 2 x + 1 = 0

Solve

x^{2} - 2 x + 1 = 0 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

4 5 x - 19 - 8 = 16

5 x + 34 - x + 22 = 2

2 x^{\frac{3}{2}} - 14 = 0

Y - 2 + 2 = 2 Y + 3

9 x - 9 = 9

What is the answer to 4=sqrt((x-1)^2)+(3-1)^2 ?
The answer to 4=sqrt((x-1)^2)+(3-1)^2 is x=1
Solve for x: 4=sqrt((x-1)^2)+(3-1)^2
The solution is x=1