What are the solutions to the equation 3t^2-27=0 ?

The solutions to the equation 3t^2-27=0 are t=3,t=-3

Find the zeros of 3t^2-27=0

The zeros of 3t^2-27=0 are t=3,t=-3

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3 t^{2} - 27 = 0

t = 3, t = - 3

Solution steps

3 t^{2} - 27 = 0

Move

27

to the right side

3 t^{2} = 27

Divide both sides by

3

t^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 9, t = - 9

9 = 3

- 9 = - 3

t = 3, t = - 3

- 5 - 2 (x - 5) = - (x + 3)

- \frac{π}{6} - π

\frac{11 v}{10} + 2 = \frac{9 v}{8}

(2 x^{4} y^{\frac{- 4}{5}}) (8 y^{2})^{\frac{2}{3}}

\frac{4 + i}{4 - i}

What are the solutions to the equation 3t^2-27=0 ?
The solutions to the equation 3t^2-27=0 are t=3,t=-3
Find the zeros of 3t^2-27=0
The zeros of 3t^2-27=0 are t=3,t=-3