What is the answer to sqrt(0.5x^2+1)=-2x ?

The answer to sqrt(0.5x^2+1)=-2x is x=-sqrt(2/7)

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sqrt(0.5x^2+1)=-2x

0.5 x^{2} + 1 = - 2 x

x = - \frac{2}{7}

Decimal Notation

x = - 0.53452 \dots

Solution steps

0.5 x^{2} + 1 = - 2 x

Square both sides:

0.5 x^{2} + 1 = 4 x^{2}

0.5 x^{2} + 1 = 4 x^{2}

Solve

0.5 x^{2} + 1 = 4 x^{2} : x = \frac{2}{7}, x = - \frac{2}{7}

x = \frac{2}{7}, x = - \frac{2}{7}

Verify Solutions:

x = \frac{2}{7}

False

, x = - \frac{2}{7}

True

The solution is

x = - \frac{2}{7}

(5 v - 22)^{\frac{2}{3}} = 4

x + x + 3 = 3

X + 4 = \frac{1}{2} X + 4

x^{\frac{6}{10}} = 2

16 - 7 x = 11

What is the answer to sqrt(0.5x^2+1)=-2x ?
The answer to sqrt(0.5x^2+1)=-2x is x=-sqrt(2/7)
Solve for x: sqrt(0.5x^2+1)=-2x
The solution is x=-sqrt(2/7)